A material of mass 1.0 x 10-2kg undergoes a fission process which decreases its mass by 0.02 percent. Calculate the amount of energy released in the process...

Assessment: WAEC SSCE - Physics - 2000 (Objective) Subject: Physics

Question 1 Report

A material of mass 1.0 x 10-2kg undergoes a fission process which decreases its mass by 0.02 percent. Calculate the amount of energy released in the process. (c = 3.0 x 108ms-1)
Answer Details
The question involves calculating the amount of energy released during a fission process, given the initial mass and the percentage decrease in mass. The formula for calculating energy released during fission is E = Δmc^2, where Δm is the decrease in mass, c is the speed of light, and E is the energy released. In this case, the mass decreased by 0.02 percent, which means Δm = 0.02/100 * 1.0 x 10^-2 kg = 2 x 10^-6 kg. Plugging this into the formula along with the speed of light (c = 3.0 x 10^8 m/s), we get: E = (2 x 10^-6 kg) x (3.0 x 10^8 m/s)^2 E = 1.8 x 10^10 J Therefore, the amount of energy released in the fission process is 1.8 x 10^10 J, which is option D.

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