Question 1 Report
(a) Triangle PQR is right-angled at Q. PQ = 3a cm and QR = 4a cm. Determine PR in terms of a.
(b) Ayo travels a distance of 24km from X on a bearing of 060° to Y. He then travels a distance of 18km to a point Z and Z is 30km from X.
(i) Draw the diagram to show the positions of X, Y and Z ; (ii) What is the bearing of Z from Y ; (iii) Calculate the bearing of X from Z.
(a)
Since triangle \(PQR\) is right-angled at \(Q\), by Pythagoras' theorem,
(b)(i) Diagram
The diagram below is drawn to scale in the correct relative positions. \(XY=24\text{ km}\) is on a bearing of \(060^\circ\), \(YZ=18\text{ km}\), and \(XZ=30\text{ km}\).
(ii) Bearing of \(Z\) from \(Y\)
Therefore, \(\angle XYZ=90^\circ\). The bearing of \(X\) from \(Y\) is \(240^\circ\). Hence,
Bearing of \(Z\) from \(Y\) = \(150^\circ\).
(iii) Bearing of \(X\) from \(Z\)
Using the cosine rule at \(Z\),
Since the bearing of \(Y\) from \(Z\) is \(150^\circ+180^\circ=330^\circ\),
Bearing of \(X\) from \(Z\) = \(277^\circ\).
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