The diagram shows a wooden structure in the form of a cone, mounted on a hemispherical base. The vertical height of the cone is 24cm and the base height 7cm...

Assessment: WAEC SSCE - General Mathematics - 1989 (Objective) Subject: General Mathematics

Question 1 Report


The diagram shows a wooden structure in the form of a cone, mounted on a hemispherical base. The vertical height of the cone is 24cm and the base height 7cm. Calculate, correct to three significant figures, the surface area of the structure. [Take \(\pi = \frac{22}{7}\)].

Answer Details

Surface area of the cone-on-hemisphere structure.

From the diagram, the common radius (from centre \(O\) to the base edge) is \(r=7\text{ cm}\), and the vertical height of the cone is \(h=24\text{ cm}\). The exposed surface is the curved surface of the cone plus the curved surface of the hemisphere; the flat circular join is internal and is not counted.

Slant height of the cone:

\[l=\sqrt{r^{2}+h^{2}}=\sqrt{7^{2}+24^{2}}=\sqrt{49+576}=\sqrt{625}=25\text{ cm}\]

Curved surface area of the cone:

\[\pi r l=\frac{22}{7}\times7\times25=22\times25=550\text{ cm}^{2}\]

Curved surface area of the hemisphere:

\[2\pi r^{2}=2\times\frac{22}{7}\times7^{2}=2\times\frac{22}{7}\times49=2\times22\times7=308\text{ cm}^{2}\]

Total surface area:

\[550+308=858\text{ cm}^{2}\]

Correct to three significant figures, the surface area is \(\mathbf{858\text{ cm}^{2}}\).

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