An orange fruit drops to the ground from the top of a tree 45m tall. How long does it takes to reach the ground? (g = 10ms-2)

Assessment: WAEC SSCE - Physics - 1991 (Objective) Subject: Physics

Question 1 Report

An orange fruit drops to the ground from the top of a tree 45m tall. How long does it takes to reach the ground? (g = 10ms-2)
Answer Details
To calculate the time it takes for the orange fruit to hit the ground, we can use the following formula: d = 1/2 * g * t^2 where d is the distance (in meters) the orange falls, g is the acceleration due to gravity (in meters per second squared), and t is the time (in seconds) it takes for the orange to fall. In this case, the orange falls from a height of 45m, and g is 10m/s^2. We can plug these values into the formula and solve for t: 45 = 1/2 * 10 * t^2 Simplifying the equation: t^2 = 9 t = 3 Therefore, it takes 3 seconds for the orange fruit to hit the ground. This is the answer to the problem.

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