Question 1 Report
A fixed mass of gas of volume 600cm3 at a temperature of 27oC is cooled at constant pressure to a temperature of 0oC. What is the change in volume?
We can use the combined gas law to solve this problem. The combined gas law states that the product of pressure and volume is directly proportional to the product of temperature and the number of moles of gas, assuming constant mass. Mathematically, this can be written as: P1V1/T1 = P2V2/T2 where P is pressure, V is volume, T is temperature, and the subscripts 1 and 2 refer to the initial and final states, respectively. We are told that the initial volume V1 is 600 cm3 and the initial temperature T1 is 27oC = 300K. We also know that the pressure P remains constant throughout the process, and that the final temperature T2 is 0oC = 273K. We can solve for the final volume V2: P1V1/T1 = P2V2/T2 V2 = (P1/P2) * (T2/T1) * V1 Since the pressure is constant, we can cancel it out, and substitute in the given values: V2 = (273K/300K) * 600 cm3 = 546 cm3 Therefore, the change in volume is 600 cm3 - 546 cm3 = 54 cm3. So, the correct answer is 54 cm3.