What is the number of oxygen atoms in 32g of the gas? (O = 16, L = 6.0 X 10,23 mol-1)

The molar mass of oxygen is 16 g/mol. This means that 1 mole of oxygen gas, which has a molar mass of 32 g/mol (since oxygen exists as O₂), contains 2 moles of oxygen atoms. We can use Avogadro's number (L = 6.0 X 10²³ mol^-1) to find out the number of oxygen atoms present in 32g of oxygen gas. First, we need to find out how many moles of oxygen gas are present in 32g: moles = mass ÷ molar mass = 32g ÷ 32 g/mol = 1 mole So, 32g of oxygen gas contains 1 mole of O₂. Since 1 mole of O₂ contains 2 moles of oxygen atoms, the number of oxygen atoms present in 32g of oxygen gas is: number of oxygen atoms = 2 moles x L = 2 x 6.0 X 10²³ = 1.2 x 10²⁴ Therefore, there are 1.2 x 10²⁴ oxygen atoms in 32g of the gas. Answer matches this result.