Which of the following gases are arranged in increasing order of diffusion rate? [H = 1 .0; C = 12; N = 14; O = 16; S = 32]

The rate of diffusion is inversely proportional to the molar mass of the gas, which means that the lighter the gas, the faster it will diffuse. Therefore, to arrange the given gases in increasing order of diffusion rate, we need to arrange them in decreasing order of their molar mass. Let's calculate the molar mass of each gas: - SO₂: 32 + 2(16) = 64 - O₂: 2(16) = 32 - NH₃: 14 + 3(1) = 17 - H₂: 2(1) = 2 - H₂S: 2 + 32 = 34 - NH₂: 14 + 2(1) = 16 - CO₂: 12 + 2(16) = 44 - N₂O: 2(14) + 16 = 44 - NO₂: 14 + 2(16) = 46 - CO₂: 12 + 2(16) = 44 Now, let's arrange the gases in decreasing order of their molar mass: - H₂, NH₃, O₂, SO₂ - NH₂, H₂S, O₂, SO₂ - CO₂, N₂O, O₂, SO₂ - CO₂, N₂, NO₂, NH₃ Therefore, the correct answer is the first option: SO₂ < O₂ < NH₃ < H₂.