Which of the following compounds of tin is a strong reducing agent?

The compound SnH₄ (tin(IV) hydride) is a strong reducing agent. This is because it can easily donate its hydrogen atoms, which act as reducing agents. In other words, SnH₄ can easily give up electrons to other compounds, causing them to be reduced. This property of SnH₄ makes it useful in a variety of chemical reactions, particularly in organic chemistry. On the other hand, SnCl₂, SnCl₄, SnO₂, and Sn(OH)₂ are not strong reducing agents. SnCl₂ and SnCl₄ are both tin(IV) compounds and do not contain any hydrogen atoms that can act as reducing agents. SnO₂ and Sn(OH)₂ contain oxygen and hydroxide groups respectively, which do not have a tendency to give up electrons and are not strong reducing agents.