Which of the following compounds of tin is a strong reducing agent?
Answer Details
The compound SnH4 (tin(IV) hydride) is a strong reducing agent. This is because it can easily donate its hydrogen atoms, which act as reducing agents. In other words, SnH4 can easily give up electrons to other compounds, causing them to be reduced. This property of SnH4 makes it useful in a variety of chemical reactions, particularly in organic chemistry. On the other hand, SnCl2, SnCl4, SnO2, and Sn(OH)2 are not strong reducing agents. SnCl2 and SnCl4 are both tin(IV) compounds and do not contain any hydrogen atoms that can act as reducing agents. SnO2 and Sn(OH)2 contain oxygen and hydroxide groups respectively, which do not have a tendency to give up electrons and are not strong reducing agents.