What volume of distilled water should be added to 400cm3 of 2.0 mole dm-3 \(H_{2}SO_{4}\) to obtain 0.20 mole dm-3 of solution>
Answer Details
This is a dilution problem in chemistry. The formula for dilution is C1V1 = C2V2, where C1 and V1 are the initial concentration and volume, respectively, and C2 and V2 are the final concentration and volume, respectively. We can rearrange the formula to solve for V2: V2 = (C1V1)/C2 Substituting the values given in the question, we get: V2 = (2.0 mol dm-3 x 400 cm3)/0.20 mol dm-3 Simplifying the expression, we get: V2 = 4,000 cm3 Therefore, 4,000cm3 of solution is needed. However, the question is asking for the volume of distilled water to add, so we need to subtract the initial volume from the final volume to get the volume of distilled water needed: Volume of distilled water = V2 - V1 = 4,000 cm3 - 400 cm3 = 3,600 cm3 Hence, the correct option is 3,600 cm3.