U varies directly as the square root of V when U = 24, V = 9, find the value of V when U = 16.

Assessment: JAMB UTME - Mathematics - 2024 Subject: General Mathematics

Question 1 Report

U varies directly as the square root of V when U = 24, V = 9, find the value of V when U = 16.
Answer Details

The relationship described in the problem is a direct variation, where U varies directly as the square root of V. In direct variation, when one variable changes, the other variable changes in a specific way. The formula for this kind of relationship is:


U = k√V


where U is directly proportional to the square root of V with k being the constant of proportionality.


From the problem statement, we know that when U = 24, V = 9, and we need to find the constant of proportionality k.


Let's substitute these values into the equation:


24 = k√9


Solving for k, we find:


24 = k * 3
k = 24 / 3
k = 8


Now we have the constant of proportionality, k = 8. To find V when U = 16, we substitute U = 16 into the equation:


16 = 8√V


Solving for √V, we find:


√V = 16 / 8
√V = 2


To find V, we square both sides of the equation:


V = 2²
V = 4


Therefore, the value of V when U = 16 is 4.

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