When the tension in a sonometer wire is doubled, the ratio of the new frequency to the initial frequency is
Question 1 Report
When the tension in a sonometer wire is doubled, the ratio of the new frequency to the initial frequency is
Answer Details
When the tension in a sonometer wire is doubled, the frequency of the sound produced by the wire changes. The formula for the frequency of the sound produced by a wire is:
f = (1/2L) √(T/μ)
Where f is the frequency, L is the length of the wire, T is the tension in the wire, and μ is the linear density of the wire.
If we double the tension T, the new frequency f' can be calculated as:
f' = (1/2L) √(2T/μ)
Now, we can simplify this equation by dividing f' by f:
f'/f = [(1/2L) √(2T/μ)] / [(1/2L) √(T/μ)]
f'/f = √(2T/μ) / √(T/μ)
f'/f = √(2T/μ) x 1/√(T/μ)
f'/f = √(2T/μ) / √(T/μ)
f'/f = √(2)
Therefore, when the tension in a sonometer wire is doubled, the ratio of the new frequency to the initial frequency is √2. represents the correct answer.
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