If loga270 - loga10 + loga \(\frac{1}{3}\) = 2, what is the value of a?

Assessment: WAEC SSCE - General Mathematics - 2006 (Objective) Subject: General Mathematics

Question 1 Report

If loga270 - loga10 + loga \(\frac{1}{3}\) = 2, what is the value of a?
Answer Details
Using the logarithmic property that loga(b) - loga(c) = loga(b/c), we can simplify the given expression as: loga(270/10) + loga(1/3) = 2 Simplifying further, we get: loga(27) + loga(1/3) = 2 Using the logarithmic property that loga(b) + loga(c) = loga(bc), we can write: loga(27 x 1/3) = 2 loga(9) = 2 Now, using the definition of logarithm, we can write: a^2 = 9 Taking the square root on both sides, we get: a = 3 or -3 However, a cannot be negative, as the base of a logarithm must be positive. Therefore, the value of a is 3. Hence, the value of a is 3.

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