(a) Give two examples each of: (i) rotational motion; (ii) linear motion. (b) Describe a laboratory experiment to determine the density of an irregularly sh...

Assessment: WAEC SSCE - Physics - 2014 (Essay) Subject: Physics

Question 1 Report

(a) Give two examples each of:

(i) rotational motion;

(ii) linear motion.

(b) Describe a laboratory experiment to determine the density of an irregularly shaped solid.

(c) State Newton's second law of motion

(d) Explain the term inertia.

(e)

The diagram above illustrates a body of mass 5.0 kg being pulled by a horizontal force F. If the body accelerates at 2.0 ms\(^{-2}\) and experiences a frictional force of 5 N, calculate the:

(i) net force on it;

(ii) magnitude of F;

(iii) coefficient of kinetic friction. [ g = 10 ms\(^{-2}\)]

 

 

Answer Details

(a) Examples of motion

(i) Rotational motion: a spinning wheel or tyre; the blades of a rotating fan; a spinning top.

(ii) Linear motion: a car moving along a straight road; a ball falling freely under gravity; an object sliding along a straight track.

(b) Experiment to determine the density of an irregularly shaped solid

  1. Find the mass \(m\) of the solid using a beam or electronic balance.
  2. Partly fill a measuring cylinder with water and note the initial volume reading \(V_1\).
  3. Tie the solid with a thin thread and lower it gently until it is fully immersed in the water. Note the new volume reading \(V_2\).
  4. The volume of the solid is \(V = V_2 - V_1\) (volume of water displaced).
  5. Calculate the density from \(\rho = \dfrac{m}{V_2 - V_1}\).

(c) Newton's second law of motion

The rate of change of momentum of a body is directly proportional to the resultant force acting on it and takes place in the direction of that force.

(d) Inertia

Inertia is the property of a body by virtue of which it resists any change to its state of rest or of uniform motion in a straight line. The greater the mass of a body, the greater its inertia.

(e) Calculations (mass \(m = 5.0\) kg, acceleration \(a = 2.0\ \text{m s}^{-2}\), friction \(f = 5\) N, \(g = 10\ \text{m s}^{-2}\); F is horizontal)

(i) Net force

\[ F_{net} = ma = 5.0 \times 2.0 = 10\ \text{N} \]

(ii) Magnitude of F

The horizontal pull provides the net force after overcoming friction:

\[ F - f = F_{net} \;\Rightarrow\; F = F_{net} + f = 10 + 5 = 15\ \text{N} \]

(iii) Coefficient of kinetic friction

The normal reaction equals the weight: \(R = mg = 5.0 \times 10 = 50\ \text{N}\).

\[ \mu = \frac{f}{R} = \frac{5}{50} = 0.1 \]

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