If 0.20 mol dm-3 NaOH(aq) was evaporated to yield 5.0g of solid NaOH, calculate the volume of NaOH (aq) used. (Na = 23.0,O = 16:0; H = 1.00)

If 0.20 mol dm^-3 NaOH_(aq) was evaporated to yield 5.0g of solid NaOH, calculate the volume of NaOH _(aq) used. (Na = 23.0,O = 16:0; H = 1.00)

Answer Details

To calculate the volume of NaOH (aq) used, we need to use the formula: moles of solute = mass of solute / molar mass of solute First, we need to find the number of moles of NaOH used to produce the 5.0 g of solid NaOH. Molar mass of NaOH = 23.0 + 16.0 + 1.0 = 40.0 g/mol Number of moles of NaOH = mass of NaOH / molar mass of NaOH = 5.0 g / 40.0 g/mol = 0.125 mol Now, we can use the formula for concentration to find the volume of NaOH (aq) used. Concentration of NaOH (aq) = 0.20 mol/dm³ Number of moles of NaOH (aq) = concentration × volume 0.125 mol = 0.20 mol/dm³ × volume Rearranging the equation to isolate the volume: volume = number of moles / concentration volume = 0.125 mol / 0.20 mol/dm³ volume = 0.625 dm³ Converting dm³ to cm³ by multiplying by 1000: volume = 0.625 dm³ × 1000 cm³/dm³ volume = 625 cm³ Therefore, the volume of NaOH (aq) used is 625 cm³. The correct option is (B).