An a.c circuit of e.m.f 12V has a resistor of resistance 8Ω connected in series to an inductor of inductive reactance 16Ω and a capacitor capacitive reactan...

Answer Details

In this AC circuit, there is a resistor, an inductor, and a capacitor connected in series. The current flow in the circuit is given by the equation I = V/Z, where V is the voltage, and Z is the impedance of the circuit. The impedance of a series circuit is given by the equation Z = sqrt(R^2 + (Xl - Xc)^2), where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance. Substituting the given values, we have: Z = sqrt(8^2 + (16 - 10)^2) Z = sqrt(64 + 36) Z = sqrt(100) Z = 10Ω The voltage is given as 12V. Therefore, the current flow in the circuit is: I = V/Z I = 12/10 I = 1.2A Hence, the answer is 1.2A.