If a force of 50N stretches a wire from 20m to 20.01m, what is the amount of force required to stretch the same material from 20m to 20.05m?
Answer Details
To solve this problem, we need to use Hooke's law, which states that the force required to stretch or compress a spring is directly proportional to the extension or compression of the spring. We can represent this law as: F = kx where F is the force applied, x is the extension or compression of the spring, and k is a constant known as the spring constant. We can use this formula to solve the problem by first finding the spring constant of the wire. To do this, we can use the given force and extension: 50N = k(20.01m - 20m) k = 50N / 0.01m k = 5000 N/m Now we can use this spring constant to find the force required to stretch the wire from 20m to 20.05m: F = kx F = 5000 N/m * (20.05m - 20m) F = 250N Therefore, the amount of force required to stretch the wire from 20m to 20.05m is 250N. Answer: 250N.