A steady current of 2A flows in a coil of emf 12V for 0.4s. A back emf of 3V was induced during this period. The stored energy in the loop that can be utili...
A steady current of 2A flows in a coil of emf 12V for 0.4s. A back emf of 3V was induced during this period. The stored energy in the loop that can be utilized is
Answer Details
Energy stored = Ivt = current x back e.m.f x time = 2 x 3 x 0.4 = 2.4J