A cell whose internal resistance is 0.5Ω delivers a current of 4A to an external resistor,The loss voltage of the cell is

Answer Details

When a cell delivers a current to an external resistor, there is a drop in voltage across the internal resistance of the cell due to the resistance of the cell. This is known as the "loss voltage" of the cell. We can use Ohm's law to calculate the loss voltage of the cell. Ohm's law states that V = IR, where V is voltage, I is current, and R is resistance. In this case, the internal resistance of the cell is given as 0.5Ω and the current delivered by the cell is 4A. Thus, the loss voltage of the cell is: V = IR = (4A)(0.5Ω) = 2V Therefore, the answer is 2.000V.