500g of water is heated so that its temperature rises from 30°C to 72°C in 7 minutes. calculate the supplied per minute. (Specific heat capacity of water is...

Assessment: WAEC SSCE - Physics - 1994 (Objective) Subject: Physics

Question 1 Report

500g of water is heated so that its temperature rises from 30°C to 72°C in 7 minutes. calculate the supplied per minute. (Specific heat capacity of water is 4200J\(kg^{-1}K^{-1}\)
Answer Details
The specific heat capacity of water is the amount of energy required to raise the temperature of 1 kg of water by 1°C. It is given as 4200 J/(kg·K). The energy required to heat the water from 30°C to 72°C can be calculated using the formula: energy = mass x specific heat capacity x temperature change Substituting the values given in the question, we have: energy = 500g x 4200 J/(kg·K) x (72°C - 30°C) energy = 500g x 4200 J/(kg·K) x 42°C energy = 8820000 J This is the total energy supplied to the water in 7 minutes. To calculate the energy supplied per minute, we need to divide this value by 7: energy per minute = 8820000 J ÷ 7 energy per minute = 1260000 J/min Therefore, the answer is 12600J.

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