An electric kettle rated 1500W boils away 0.3kg of a liquid at its boiling point every 300s. Calculate the specific latent heat of the vaporisation of the l...

Answer Details

The specific latent heat of vaporization is the amount of energy required to change the state of a unit mass of a substance from liquid to gas, without a change in temperature. To find the specific latent heat of vaporization, we can use the formula: specific latent heat = power x time / mass where power is the power rating of the electric kettle, time is the time taken to boil away the liquid, and mass is the mass of the liquid boiled away. Substituting the given values: specific latent heat = 1500W x 300s / 0.3kg = 1.5 x \(10^6Jkg^-1\) Therefore, the specific latent heat of vaporization of the liquid is 1.5 x \(10^6Jkg^-1\). Answer: 1.5 x \(10^6Jkg^-1\)