A conductor has a diameter of 1.00mm and length of 2.00m. If the resistance of the material is 0.1Ω, the resistivity is

Answer Details

The formula for resistivity is given by ρ = RA/l, where R is the resistance, A is the cross-sectional area of the conductor, and l is the length of the conductor.
In this case, the diameter of the conductor is given as 1.00mm, so the radius is 0.5mm or 0.0005m. The cross-sectional area A of the conductor is given by A = πr^2 = π(0.0005m)^2 = 7.85 x 10^-7 m^2. The length of the conductor is given as 2.00m, and the resistance is given as 0.1Ω.
Substituting these values into the formula for resistivity, we get:
ρ = RA/l = (7.85 x 10^-7 m^2 x 0.1Ω) / 2.00m
Simplifying this expression, we get:
ρ = 3.925 x 10^-9 Ωm
Therefore, the answer is option (D) 3.93 * 10^-8 Ωm.