An engine of a car of power 80 kW moves on a rough road with a velocity of 32 ms-1. The forces required to bring it to rest is

Answer Details

In terms of dimension: power , P, = ML2T3 Force F1 = MLT-2; Vel, V, LT-1 From the above, => P = F x V i.e, ML2T-3 = MLT-2 x LT-1 ML2T-3 => 80,000 = F x 32