If two charged plates are maintained at a potential difference of 3 kv, the work done in taking a charge of 600µc across the field is

Answer Details

When a charge moves through an electric field, the work done on the charge is given by the formula W = QV, where Q is the charge and V is the potential difference across which the charge moves. In this case, the potential difference across the charged plates is 3 kV, and the charge that is moved across the field is 600 µC (or 6.0 × 10^-4 C). Therefore, the work done is:
W = QV = (6.0 × 10^-4 C)(3 × 10^3 V) = 1.8 J
So the correct answer is 1.8J.