Given that \(\frac{6x-y}{x+2y}=2\), find the value of \(\frac{x}{y}\)

Assessment: WAEC SSCE - General Mathematics - 1998 (Objective) Subject: General Mathematics

Question 1 Report

Given that \(\frac{6x-y}{x+2y}=2\), find the value of \(\frac{x}{y}\)
Answer Details
We are given that: \[\frac{6x-y}{x+2y}=2\] To solve for \(\frac{x}{y}\), we can simplify the equation above and isolate \(\frac{x}{y}\). We start by cross multiplying both sides of the equation: \[6x-y=2(x+2y)\] Expanding the brackets, we get: \[6x-y=2x+4y\] Simplifying and isolating \(x\), we get: \[4x=5y\] Therefore, \(\frac{x}{y}=\frac{5}{4}\). Hence, the answer is \(\frac{5}{4}\).

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