In dilute solution the heat of the reaction \( \mathrm{NaOH + HCl = NaCl + H_2O} \) is - 57.3kJ. Therefore the heat of the reaction \( \mathrm{2NaOH + H_2SO...

Assessment: JAMB UTME - Chemistry - 1984 Subject: Chemistry

Question 1 Report

In dilute solution the heat of the reaction \( \mathrm{NaOH + HCl = NaCl + H_2O} \) is - 57.3kJ. Therefore the heat of the reaction \( \mathrm{2NaOH + H_2SO_4 \rightarrow Na_2SO_4 + 2H_2O} \) is

Answer Details
NaOH + HCl = NaCl + H2O  Δ H = -57.3kJ

Heat of reaction of 2NaOH + H2O4

NaSO4 + H2O is

= 57.3 x 2 = -114.6 kJ

Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)
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