Find the equation of a straight line parallel to the line 2x - y = 5 and having intercept of 5

To find the equation of a straight line parallel to 2x - y = 5, we need to determine the slope of the given line. The slope of a line is defined as the change in y divided by the change in x, which can be written as Δy/Δx. We can rewrite 2x - y = 5 as y = 2x - 5, which is in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. From this form, we can see that the slope of the line is 2. A line parallel to this line will have the same slope of 2. We also know that the new line has an intercept of 5, which means it passes through the point (0, 5). Using the point-slope form of a line, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can substitute m = 2 and (x1, y1) = (0, 5) to get the equation: y - 5 = 2(x - 0) Simplifying this equation gives: y = 2x + 5 Therefore, the equation of a straight line parallel to 2x - y = 5 and having intercept of 5 is 2x + y = 5. Option (a) is the correct answer.