Three capacitors each of capacitance 1.5\(\mu F\) are connected in series. The total capacitance in the circuit is
Question 1 Report
Three capacitors each of capacitance 1.5\(\mu F\) are connected in series. The total capacitance in the circuit is
Answer Details
When capacitors are connected in series, the reciprocal of the total capacitance is equal to the sum of the reciprocals of the individual capacitances. Mathematically, we can express it as:
\(\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} + ...\)
In this case, we have three capacitors of equal capacitance, so we can simplify the equation to:
\(\frac{1}{C_{total}} = \frac{1}{1.5\mu F} + \frac{1}{1.5\mu F} + \frac{1}{1.5\mu F}\)
\(\frac{1}{C_{total}} = \frac{3}{1.5\mu F}\)
\(\frac{1}{C_{total}} = 2\)
\(C_{total} = \frac{1}{2}\mu F\)
Therefore, the total capacitance in the circuit is 0.5 \(\mu F\), which is option (D).
Download The App On Google Playstore
Everything you need to excel in your exams
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning