Calculate the magnitude of the force required to just move a 20kg object along a horizontal surface if the coefficient of friction is 0.2. [g = 10ms-2]

Calculate the magnitude of the force required to just move a 20kg object along a horizontal surface if the coefficient of friction is 0.2. [g = 10ms-2]

Answer Details

The force required to move an object along a surface is equal to the product of the coefficient of friction and the normal force acting on the object. The normal force is equal to the weight of the object, which is given by the product of the mass and the acceleration due to gravity. Therefore, the force required to move the 20kg object along a horizontal surface is: Force = coefficient of friction * normal force Normal force = mass * acceleration due to gravity = 20kg * 10ms^-2 = 200N Force = 0.2 * 200N = 40N Therefore, the magnitude of the force required to just move the 20kg object along a horizontal surface is 40N. The correct option is: 40.0N