Heat is supplied to a test tube containing 100g of ice at its melting point. The ice melts completely in 1 min.What is the power rating of the source of hea...

Assessment: JAMB UTME - Physics - 1994 Subject: Physics

Question 1 Report

Heat is supplied to a test tube containing 100g of ice at its melting point. The ice melts completely in 1 min.What is the power rating of the source of heat? [Latent heat of fusion of ice = 336Jg-1]
Answer Details
When heat is supplied to the ice, the ice will absorb heat and its temperature will rise until it reaches its melting point. At this point, the ice will start melting, and the temperature will remain constant until all the ice has melted. The energy required to melt 1 gram of ice at its melting point is called the latent heat of fusion of ice and is given as 336J/g. In this question, we are given that 100g of ice melts completely in 1 min. Therefore, the total energy required to melt the ice can be calculated as follows: Total energy = mass x latent heat of fusion of ice Total energy = 100g x 336J/g Total energy = 33600J Since this energy is supplied in 1 minute, we can calculate the power rating of the source of heat as follows: Power = Total energy supplied / time taken Power = 33600J / 60s Power = 560W Therefore, the power rating of the source of heat is 560W. Option (C) is the correct answer.

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