If it takes 5.0 hrs to drain a container of 540.0cm3 of water, what is the flow rate of water from the container in kg-1? [Density of water = 1000kgm-3]

Answer Details

The flow rate of water is the volume of water drained per unit time. To calculate it, we first need to find the volume of water drained, which is given as 540.0 cm^3. To convert this to liters, we divide by 1000: 540.0 cm^3 = 0.54 L We are given the time taken to drain this volume of water as 5.0 hours. To convert this to seconds, we multiply by 3600: 5.0 hours = 18000 s The flow rate of water is therefore: Flow rate = Volume / Time = 0.54 L / 18000 s Now, we are given the density of water as 1000 kg/m^3. To convert the volume of water to mass, we multiply by the density and convert the units from liters to kilograms: 0.54 L × 1000 kg/m^3 × 10^-3 L/kg = 0.54 kg Putting it all together, the flow rate of water is: Flow rate = Volume / Time = 0.54 kg / 18000 s = 0.03 × 10^-3 kg/s = 30.0 kg^-1 s^-1 Therefore, the answer is option D, 30.0 kg^-1 s^-1.