A Motor Tyre is inflated to pressure of 2.0 x 105Nm-2 when the temperature of air is 27oC. What will be the pressure in it at 87oC assuming that the volume ...

Answer Details

The pressure inside a motor tire is directly proportional to the temperature of the air inside it. According to the Gay-Lussac's Law of pressure-temperature, when the temperature of gas increases, its pressure also increases if the volume is constant. Here, the volume of the tire is assumed to be constant. Using the formula P1/T1 = P2/T2, where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure, and T2 is the final temperature, we can find the final pressure. Substituting the given values, we get: P1 = 2.0 x 10^5 N/m^2 T1 = 27°C + 273 = 300K T2 = 87°C + 273 = 360K So, P2 = (P1 x T2) / T1 = (2.0 x 10^5 N/m^2 x 360K) / 300K = 2.4 x 10^5 N/m^2. Therefore, the pressure inside the motor tire at 87°C is 2.4 x 10^5 N/m^2. So, the answer is 2.4 x 10^5 N/m^2.