How long would it take to deposit 0.08g of copper from CuCl2 solution by passing a current of 0.5A?
[Cu = 64, F = 96500 C mol-1]
Answer Details
Cu2+ + 2e → Cu(s) 2 * 96500C deposit 64g of Cu ∴ x quantity of electricity wil deposit 0.08 x = (2 * 96500 * 0.08)/64 =241.25 coulomb. Q = It 241.25 = 0.5t t = 241.25/60 = 8 mins