C2H4(g) + H2(g) → C2H6(g) ΔH = -137kJ mol-1 The reaction represented above is

C2H4(g) + H2(g) → C2H6(g) ΔH = -137kJ mol-1

The reaction represented above is

Answer Details

The reaction represented in the given equation involves the reactants carbon dioxide (CO2) and hydrogen gas (H2) to form the product, ethane (C2H6), with the release of energy (enthalpy change, ΔH) of -137 kJ/mol. As the reaction releases energy in the form of heat, it is exothermic. The negative value of ΔH indicates that the reaction is exothermic.