A particle in circular motion performs 30 oscillation in 6 seconds. Its angular velocity is
Question 1 Report
A particle in circular motion performs 30 oscillation in 6 seconds. Its angular velocity is
Answer Details
The frequency of oscillation is given by the number of oscillations divided by time taken for the oscillations, which is: f = number of oscillations / time In this case, the particle performs 30 oscillations in 6 seconds, so the frequency is: f = 30 / 6 = 5 Hz The angular velocity (ω) is related to frequency (f) by the formula: ω = 2πf Substituting the value of frequency (f) into the formula, we get: ω = 2π × 5 = 10π rad s^-1 Therefore, the correct option is: 10π rad s-1
Download The App On Google Playstore
Everything you need to excel in your exams
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning