The energy stored in a capacitor of capacitance 10μF carrying a charge of 100μC
Answer Details
The energy stored in a capacitor is given by the formula:
E = 1/2 * C * V^2
where E is the energy stored, C is the capacitance of the capacitor, and V is the voltage across the capacitor.
Since the capacitor is carrying a charge of 100μC, the voltage across the capacitor can be calculated using the formula:
V = Q/C
where Q is the charge on the capacitor and C is the capacitance.
Substituting the given values, we get:
V = Q/C = 100μC/10μF = 10V
Now substituting the values of C and V in the energy formula, we get:
E = 1/2 * C * V^2 = 1/2 * 10μF * (10V)^2 = 500μJ
So the energy stored in the capacitor is 500μJ, which is equivalent to 5 x 10^-4 J (in scientific notation). Therefore, the answer is option (D) 5 x 10^-4 J.