Two force each of 10N acts on a body, one towards the north and the other towards the east.

The magnitude and the direction of the resultant force are

Answer Details

The problem gives us two forces acting on a body: one 10N force towards the north and the other 10N force towards the east. To find the magnitude and direction of the resultant force, we can use vector addition. We can draw a diagram where the two forces are represented as arrows with their tails at the same point. Using the Pythagorean theorem, we can find the magnitude of the resultant force by finding the hypotenuse of the right triangle formed by the two forces. $R = \sqrt{(10N)^2 + (10N)^2} = 10\sqrt{2}N$ To find the direction of the resultant force, we can use trigonometry. We can find the angle between the resultant force and the x-axis (east) by taking the inverse tangent of the ratio of the y-component (north) to the x-component (east) of the resultant force. $\theta = \tan^{-1}(\frac{10N}{10N}) = 45°$ Therefore, the magnitude and direction of the resultant force are 10√2N and 45°E. The answer is: 10√2N, 45°E.