An elements X with relative atomic mass 16.2 contains two isotopes 168X with relative abundance of 90% and m8X with relative abundance of 10%. The value of ...

An elements X with relative atomic mass 16.2 contains two isotopes 168X with relative abundance of 90% and m8X with relative abundance of 10%. The value of m is

Answer Details

168X, m8X
16 * (90/100) + m * (10/100) = 16.2
1440 + 10m = 1620
10m = 180
m = 18