What volume of CO2 at s.t.p would be obtained by reacting trioxocarbonate (IV) with excess acid?(G.M.V at s.t.p = 22.4 dm3)

The balanced equation for the reaction between trioxocarbonate (IV) and an acid is: CO2(g) + 2H+(aq) → H2O(l) + CO2(g) From the equation, we can see that one mole of trioxocarbonate (IV) reacts with two moles of H+ to produce one mole of CO2. At standard temperature and pressure (STP), one mole of any gas occupies 22.4 dm3 (or 22,400 cm3). Since the question states that there is an excess of acid, we can assume that all the trioxocarbonate (IV) will react, meaning that we only need to consider the amount of CO2 produced from one mole of the compound. Therefore, the volume of CO2 at STP produced from one mole of trioxocarbonate (IV) is 22.4 dm3 (or 22,400 cm3). Therefore, the correct answer is option B: 22.40 cm3.