a thermometer records 680 mmHg at steam point and 440 mmHg at ice point. The temperature it records at 380 mmHg is

Answer Details

To find the temperature at 380 mmHg, we need to interpolate between the steam and ice points. We can use the formula: t = ((P - P_ice) / (P_steam - P_ice)) x (T_steam - T_ice) + T_ice where: - t is the temperature we want to find - P is the pressure we want to use for interpolation (380 mmHg in this case) - P_ice is the pressure at the ice point (440 mmHg) - P_steam is the pressure at the steam point (680 mmHg) - T_ice is the temperature at the ice point (0^oC) - T_steam is the temperature at the steam point (100^oC) Plugging in the values, we get: t = ((380 - 440) / (680 - 440)) x (100 - 0) + 0 t = (-60 / 240) x 100 t = -25^oC Therefore, the temperature recorded at 380 mmHg is -25^oC.