A nuclide represented as \(^{70}_{32}X\) has a neutron-proton ratio of
Question 1 Report
A nuclide represented as \(^{70}_{32}X\) has a neutron-proton ratio of
Answer Details
The neutron-proton ratio of a nuclide is the ratio of the number of neutrons (N) to the number of protons (Z) in its nucleus.
For the nuclide \(^{70}_{32}X\), the number 70 represents the total number of nucleons (protons + neutrons) in its nucleus, while 32 represents the number of protons. Therefore, the number of neutrons can be calculated as:
N = 70 - 32 = 38
The neutron-proton ratio of this nuclide can then be calculated as:
N/Z = 38/32 = 1.19
Therefore, the neutron-proton ratio of this nuclide is approximately 1.2, which corresponds to.
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