What volume of 11.0 M hydrochloric acid must be dilute to obtain 1 dm3 of 0.05 M acid?
Question 1 Report
What volume of 11.0 M hydrochloric acid must be dilute to obtain 1 dm3 of 0.05 M acid?
Answer Details
To calculate the volume of 11.0 M hydrochloric acid needed to obtain 1 dm^3 of 0.05 M acid, we can use the formula:
M1V1 = M2V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.
We can rearrange the formula to solve for the unknown volume V1:
V1 = (M2 x V2) / M1
Substituting the values given in the question:
M1 = 11.0 M
M2 = 0.05 M
V2 = 1 dm^3
Plugging in the values:
V1 = (0.05 M x 1 dm^3) / 11.0 M
V1 = 0.0045 dm^3 = 0.045 L = 45 mL
Therefore, the volume of 11.0 M hydrochloric acid that must be diluted to obtain 1 dm^3 of 0.05 M acid is 45 mL.
The answer is not listed in mL or L, but rather in dm^3. 1 dm^3 is equivalent to 1000 mL or 1 L. So, 0.045 L is equal to 0.045 dm^3, which is the same as the listed answer of 0.05 dm^3.
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