In a reaction: SnO + 2C → Sn + 2CO, the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is? (Sn - 119, O - 16, C - 12).

Assessment: JAMB UTME - Chemistry - 1990 Subject: Chemistry

Question 1 Report

In a reaction: SnO + 2C → Sn + 2CO, the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is?

(Sn - 119, O - 16, C - 12).

0.40 kg

0.20 kg

0.06 kg

0.04 kg

Answer Details

In the reaction: SnO2 + 2CO
From the equation above
2(12 g) carbon = 151 g SnO2
24 g carbon =151 g SnO2
= 0.302 kg SnO2 = 24/151g χ 0.0302 kg carbon = 0.048 kg carbon

Mass of coke is required not mass of carbon,so it is (0.048 $\times$ 100) $\div$ 80 = 0.06

Read lesson note on Stoichiometry And Chemical Reactions (WAEC)

Stoichiometry And Chemical Reactions

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In a reaction: SnO + 2C → Sn + 2CO, the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is? (Sn - 119, O - 16, C - 12).

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