A fair die is tossed twice. Find the probability of obtaining a 3 and a 5.
Answer Details
When a die is tossed, there are six possible outcomes, each with equal probability. Therefore, the probability of getting a 3 on the first toss is 1/6, and the probability of getting a 5 on the second toss is also 1/6. Since we want both events to occur, we need to multiply their probabilities:
\[\frac{1}{6} \times \frac{1}{6} = \frac{1}{36}\]
So, the probability of obtaining a 3 and a 5 is 1/36. Therefore, the correct option is:
- \(\frac{1}{36}\)