The same current is passed for the same time through solutions of AgNO3 and CuSO4 connected in series. How much silver will be deposited if 1.0 g of copper ...

Answer Details

From Faraday;s second law of electrolysis

$\frac{\text{Mass of silver deposited}}{\text{Mass of copper deposited}}$ = $\frac{\text{Equivalent mass of silver}}{\text{Equivalent mass of copper}}$

$\frac{\text{Mass of silver deposited}}{1.0g}$ = $\frac{108}{63.5}$

= 31.75g

Copper is devalent = Cu2+

Mass of silver deposited = $\frac{108g}{31.75g}$

= 3.30g