Two identical cells each of e.m.f 2v and internal resistance 1.0\(\Omega\) are connected in parallel. The combination is connected to an external load of 1....

To calculate the current in the circuit, we can use the following steps: 1. Find the equivalent internal resistance of the two cells in parallel: When two resistors are connected in parallel, their equivalent resistance is given by: 1/R_eq = 1/R₁ + 1/R₂ + ... Here, R₁ = R₂ = 1.0\(\Omega\) So, 1/R_eq = 1/1.0\(\Omega\) + 1/1.0\(\Omega\) => 1/R_eq = 2/1.0\(\Omega\) => R_eq = 0.5\(\Omega\) 2. Find the total e.m.f of the two cells in parallel: When two e.m.f sources are connected in parallel, their total e.m.f is the same as the e.m.f of each cell, i.e., 2V in this case. 3. Calculate the total current in the circuit: Using Ohm's law, the total current in the circuit is given by: I = E / (R_ext + R_eq) Here, E is the total e.m.f (2V), R_ext is the external resistance (1.5\(\Omega\)), and R_eq is the equivalent internal resistance of the two cells (0.5\(\Omega\)). => I = 2V / (1.5\(\Omega\) + 0.5\(\Omega\)) => I = 2V / 2\(\Omega\) => I = 1.0A Therefore, the current in the circuit is 1.0A. The correct answer is.