A platinum resistance thermometer has a resistance 4\(\Omega\) at 0oC and 10\(\Omega\) at 100oC. Assuming the resistance changes uniformly with temperature....

A platinum resistance thermometer has a resistance 4\(\Omega\) at 0oC and 10\(\Omega\) at 100oC. Assuming the resistance changes uniformly with temperature. Calculate the resistance of the thermometer when the temperature is 45oC.

Answer Details

The resistance of a platinum resistance thermometer changes uniformly with temperature. Let's use the formula for the resistance-temperature relationship of a platinum resistance thermometer: R = R₀(1 + αT) Where R is the resistance at a given temperature T, R₀ is the resistance at 0°C (4Ω in this case), and α is the temperature coefficient of resistance of platinum. We can find α by using the resistance values at two different temperatures, say 0°C and 100°C: α = (R₁ - R₀) / (R₀ × ΔT) Where ΔT is the temperature difference between the two resistance values (100°C - 0°C = 100°C), and R₁ is the resistance at the higher temperature (10Ω in this case). α = (10Ω - 4Ω) / (4Ω × 100°C) = 0.015Ω/°C Now we can use the formula to find the resistance at 45°C: R = R₀(1 + αT) = 4Ω(1 + 0.015Ω/°C × 45°C) ≈ 6.7Ω Therefore, the answer is 6.7Ω.