The electric field intensity in a place where a charge of 10-10c experiences a force of 0.4N is?

Assessment: JAMB UTME - Physics - 2005 Subject: Physics

Question 1 Report

The electric field intensity in a place where a charge of 10-10c experiences a force of 0.4N is?
Answer Details
The electric field intensity can be calculated using the formula: E = F/Q, where E is the electric field intensity, F is the force experienced by the charge Q. Substituting the values given in the question, we have: E = F/Q = (0.4N)/(10^-10C) Simplifying this expression, we get: E = 4.0 x 10^9 NC^-1 Therefore, the electric field intensity in the given place is 4.0 x 10^9 NC^-1, which is option D.

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