The electric field intensity in a place where a charge of 10-10c experiences a force of 0.4N is?

Answer Details

The electric field intensity can be calculated using the formula: E = F/Q, where E is the electric field intensity, F is the force experienced by the charge Q.
Substituting the values given in the question, we have:
E = F/Q = (0.4N)/(10^-10C)
Simplifying this expression, we get:
E = 4.0 x 10^9 NC^-1
Therefore, the electric field intensity in the given place is 4.0 x 10^9 NC^-1, which is option D.