In the figure above, the coefficient of static friction is 0.5. If the tension in the string is T, the acceleration of the system in motion is
Answer Details
Normal reaction R = 3 kg x 10 = 30N coefficient of friction , μ = 0.5 ∴ acting frictional force = μR = 30 x 0.5 Pulling/sliding force F = 6kg x 10 = 60N. ∴ Net downward force = ma = 60 - 15.0 => (3 + 6)a = 45 ∴ 9a = 45 a = 5m/s2