the shortest length of the air column in a resonance tube at resonance is 0.12m and the next resonance length is 0.37m. calculate the frequency of vibration...
Question 1 Report
the shortest length of the air column in a resonance tube at resonance is 0.12m and the next resonance length is 0.37m. calculate the frequency of vibration given that the speed of sound in air is 340m-1
Answer Details
The difference between the first and second resonance lengths is equal to half the wavelength of the sound wave. Hence, the wavelength is:
λ = 2 × (0.37m – 0.12m) = 0.5m
The speed of sound is given as 340m/s. We can use the formula:
v = fλ
where v is the velocity of sound, f is the frequency of vibration, and λ is the wavelength of the sound wave.
Substituting the values we get:
340 = f × 0.5
Solving for f, we get:
f = 680 Hz
Therefore, the frequency of vibration is 680Hz.
So, the answer is 680Hz.
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