Which of the following gives a precipitate when treated with NaOH solution?

When NaOH (sodium hydroxide) solution is added to AlCl3 (aluminum chloride), it reacts to form a precipitate, which is a solid that separates out of a solution. The reaction between AlCl3 and NaOH is as follows: AlCl3 + 3NaOH -> Al(OH)3 (precipitate) + 3NaCl (salt) On the other hand, when NaOH solution is added to NH4Cl (ammonium chloride), there is no precipitate formed. Instead, the reaction between NH4Cl and NaOH is as follows: NH4Cl + NaOH -> NH3 (ammonia gas) + NaCl (salt) When NaOH solution is added to CH3COONa (sodium acetate), there is also no precipitate formed. Instead, the reaction between CH3COONa and NaOH is as follows: CH3COONa + NaOH -> CH3COOH (acetic acid) + Na2CO3 (sodium carbonate) Finally, when NaOH solution is added to Na2CO3 (sodium carbonate), there is also no precipitate formed. Instead, the reaction between Na2CO3 and NaOH is as follows: Na2CO3 + NaOH -> Na2CO3 (sodium carbonate) + H2O (water) In summary, only AlCl3 forms a precipitate when treated with NaOH solution.